ANSWERS: 9
  • They should. It's the old feather and the hammer thing.
  • I don't think so. The lighter one will be more affected by buoyancy, right? Suppose that one weighs the same amount as the water that it displaces. It will not fall whereas the other one will.
  • I believe they will go to the bottom at the same time!
  • Question to clarify the problem: do they both have densities greater than that of water (1g/mL)? It's possible that neither one will even touch the bottom at all.
  • If they are the same size then the heavier one would sink faster, think of a wood piece and a stone, even if they are the same size the stone would hit bottom faster When a solid object is placed in a fluid such as a liquid or gas, there is a buoyant force pushing the object upward. When that force is greater than the downward force of gravity, the object will float to the top of the fluid. Otherwise it will sink or remain in place in the fluid. The fact that it is the same size but wheight more makes the second one more dense. The density (d) of a material is its mass (m) divided by its volume (V). The equation for density is: d = m / V. Now the question remains will it sink at all ? we really dont have any messurements so we could have a case where both ithems dont sink at all. If an object weighed more than an equal volume of fluid--in other words, its density was greater, then the downward pressure at its bottom would be the weight of the fluid above plus the weight of the object.This force would be more than the upward force, due to only the weight of the water. Since the downward force is greater than the upward force, the object would sink. The second and heavier object would hit first given that it has a density greater than the liquid ( lake).
  • No, if they were dropped in air they would, but not through water, cause a heaver object sinks faster,...Unless the heavier item happens to be less dense than water, then the lighter one will hit first and the heavier one will float.
  • This question has nothing to do with weight and volume,but the density.(suppose an infinite area of the surface) Let's use p and p0 to denote the density of an object and water respectively. (1)p<p0,the object won't sink. (2)p=p0,it depends on the external conditions (3)p>p0,after the object has totally sink into the water,the acceleration will be: a=(pgV-p0gV)/pV=(1-p0/p)g so,the higher the density is,the shorter the time will be. In fact,the process is more complex when the object hasn't totally sunk into the water.But if the lake is deep enough,we can neglect this process.
  • the heavier one will touch first. if the objects were the same density and shape but not neccesarily same size ans weight then they would touch at the same time.
  • Force down depends on weight, and force up depends on buoyancy, size, and water resistance (which depends on speed). So the two bodies have very little resemblance. But the heavier body will hit bottom first, if it doesn't float. This is not a simple situation.

Copyright 2018, Wired Ivy, LLC

Answerbag | Terms of Service | Privacy Policy