ANSWERS: 2
  • The middle number in each row follows n^2: Row Middle number 1 1 2 (4) 3 9 4 (16) 5 25 Therefore, the middle number of the 99th row is 99^2 = 9801 The sum of the numbers in each row follows n^3: Row Sum 1 1 2 8 3 27 4 64 Therefore, the sum of row 30 is 30^3 = 27,000
  • I have another one for u since u'r so good at this. If all of the digits must be different, how many 3-digit odd nmbers greater than 700 can be written using only the digits 1, 2, 3, 5, 6, and 7?

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